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2.bj.cn(Ãâó: books.google.com)
... bj pr cn / T ( Y ; 2 ) C and c ( 1 ) DX , y / 0 ; + / T ( Y ; 2 ) C Type of process Interchange between C ( 2L ) and C ( 2R ) Interchange between C ( 2L ) and Sc3 . Y Nondisjunction of compounds Progeny of un- known Total progeny in ...
2.bj.cn(Ãâó: books.google.com)
... CN ¥Â¥É DK AH DH AR 20 −BG — BJ BHCIBYAZDG — AT- DR BL DQ QA CM A .................. 0 CU BE AX AU DE AD AF BO CF -BF ... 2 BK ¥Â¥É BY DQ AH CU AL DG DE DF CF BX CI QA CE AZ BH BG BQ DL CM AV BV AR BE CG CH DH BP Wood With braces ...
2.bj.cn(Ãâó: books.google.com)
... CN BI DK AH DH AR 20 BG BJ BHCI BY AZ DGAT DR BL DQ QA CM !! .................. Wood CU -CZ- DA AA AC -DD CP DE AB ... 2 BK BH AA DA BO AD DC AH DG BW ᎠᏴ DE AF DF ¥Â¥É BY DQ BX CI QA CE AZ CU AL DP CF BV BE BG BQ DL CM AV AR CG CH ...
2.bj.cn(Ãâó: books.google.com)
... BJ; 1.26. Above; C.N. 2. BJ is equal to CJ; Hence, HJ is equal to JK; Above. C.N. 1. Similarly, each of HG, GL and LK can be shown to be equal to each of HJ and JK; Hence, pentagon GHJKL is equilateral. So, I say it is also equiangular ...
2.bj.cn(Ãâó: books.google.com)
... (b j ) = 0 and ¥÷ b j (b j ) > 0. We now make the scaling (2.7.18) v cN 2/3 , c = ¥÷ bj (¥âj ). u x = b j + cN 2/3 , y = bj + Then as N ¡æ ¡Ä, b j (2.7.19) ( 01 ) ¥Õ r ( N2/3¥÷ b j ) −1¥Õ r ( 1 ) 0 (y) ( N2/3¥÷ (x) ) = −2¥ði ( Ai(u) Ai ...
2.bj.cn(Ãâó: books.google.com)
... bj.cn 2 School of Computer Science and Technology, Beijing University of Posts and Telecommunications, 10 Xi Tu Cheng Rd, Beijing 100876, China chjl@bupt.edu.cn Abstract. Former approaches to VHE resulted in considerable traffic ...
2.bj.cn(Ãâó: books.google.com)
... Cn - 2 Row zo z1 z2 1 bo b1 b2 2 bn- -1 bn- z " -j ... ... : C2 Cn - 3 5 do d1 d2 ... 6 dn - 2 dn - 3 -2 dn - 4 :: ... :: ... bn - j bj Cn - j Cj - 1 dn - j dj - 2 ... ... ... 2220 2n 2n - 4 54 fo £ 3 55 f2 f3 fi fo 2n ...
2.bj.cn(Ãâó: books.google.com)
... Bj , Cn , Am Like 1. ( a ) with C , on the left . 1. ( c ) Like 1. ( a ) with B ; on the left . 1. ( d ) Like 1. ( c ) with Cn on the left . 2. ( a ) d A ;; THA d THA ; A ; THA , Cn ; A , THA , B , Cn , Am 2. ( 6 ) Ak ; Bj , THA Am , Cn , ...
2.bj.cn(Ãâó: books.google.com)
... 2 BJ ( Cn from H. Gl ..... Gn - 1 ) ; X [ S , B1 ..... 3 2x C ] ( C from H * .Gl ..... Gn ) end x [ < env > Sx + exp 2x Cx + exp by x + V [ exp ] ; x [ s , Dr CG from H * ) end X Since X [ SC has the property of correctly transforming.
2.bj.cn(Ãâó: books.google.com)
... 2 " -1 z " 123 ¬Ñ¬à 17 2 an 4 5 Co C1 C2 ... 6 Cn - 2 Cn - 3 Cn - 4 ... an - 1 bo b1 a2 an - 2 b2 bn - 1 bn - 2 bn - 3 ... ... ... ... an - j aj bn - j bj ... Cn - 2 bo an - 1 ai ¬Ñ¬à bn - 1 an Co Note that the elements of even rows consist ...