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s.xjh.cn(来源:books.google.com)
... (Xjh)dZaj(X)\ < Cj,ah-kJ-S\a\X(Xjh)m(Xr = Cj,ah-k^a^hx(Xjh)m(Xr (since Xjh < 2 in the support of X) <2cha^h-ki-l-s\a ... CN)^y"(Rn;CN) is continuous. In particular, by virtue of (9.3), this is the case also for a 6 S°s(m»,g;MN). As ...
s.xjh.cn(来源:books.google.com)
... xjh * Pas xqs α k = 0 Pi h = hjp + 1 Pj s = 0 Pq Ma h = hjẞ k = kia ≤a , ≤ẞ , > d Ui , j , q ( 2 ) = Σ Pik Nik * Σ Pjh xjh * Σ Pqs xqs 8 α < a , ≤B , > d Ui , j , q k = 0 Pi k = kia h = hjp Ма ( 2 ) = Σ Σ ΣΣ Pi k = 0 h = 0 s = sq8 ...
s.xjh.cn(来源:books.google.com)
... (S) = U can be found sich that for every I Nuss) there exist a subdivision (Bsishes & of S into pairwise disjoint sets whose union is S, and Nss C N ... (xjh)p(Sjh). Let us prove that {u}} is a Cauchy sequence in U. 6 4.9, do this, let 6 ...
s.xjh.cn(来源:books.google.com)
... S xi ( π ( xjh , t ) –πτ xj ) - π ( ht , xj ) ) + x ; ( π + ( xi , ht ) - π ( xih , t ) ) + t ( π + ( xj , xih ) – π ( xi , xjh ) ) S + Qs ( xi , xjh , t ) – Qs ( xj , xih , t ) - Qs ( xi , ht , xj ) . S From the assumption ( B ) k , we ...
s.xjh.cn(来源:books.google.com)
... xjh ≠ i m m ΣΣ ( 3 ) t = 1s = 1 tx , y , 0 2 Multiplying equation 85 by SyYi ii st F ae ( ) ( ) tx , y , ( ) s ≠ t χ . , θ j xj , y , t # s 2 xj , t j ' and summing over i , t ƏY t t i Y ix xhi Ji ( 84 ) Y * jh ≠ i i aY ix , Y j.h ...
s.xjh.cn(来源:books.google.com)
... S = S1S2 (a) Sample space S1 Figure 2.10 Sample Spaces for Channel Input and Output and Respective Their Product ... x j h log P ^ x j h = P ^ x j h =/nk= 1 P ^ xj , yk h HY ^ h = -. /. n = P ^ yk h log P ^ yk h k 1 P ^ yk h = /mj.
s.xjh.cn(来源:books.google.com)
... s , respectively . 0 100 G ( x ; hj , v ; ) -10 G ( x , hj.2 ) G ( x , hj , v1 ) G ( xjh , v1 ) G ( xj , h , 2 ) G ( xjh.v1 ) G ( xj.h , -10 0 X 10 0 h 3 ( b ) ( a ) Figure 2.16 : Heat fluxes G , ( x ; h ,, v ) , Gs ( x ;; h , v ; ) ( i ...
s.xjh.cn(来源:books.google.com)
... Xjh , E ( I ) . Then from [ h ] , ( 9 ) D ; ( 8 ) D2 ( s ) hj , j ( s ) ds = || w || 2 = = ( ( Eß – Eα ) P ( π ( x ̧u ) ) , π ( w ) ) ≤ || u || · || w || || W || = || X ¡ h11 , J || ≤ || u || ⋅ Since J is arbitrary , hл1 , л € Е ( I ) ...
s.xjh.cn(来源:books.google.com)
... s ; Є M ( uj + \ jh ) we have — ( HI ( u ; + Xjh ) ( H ( uj + λjh ) – H ( uj ) ) 1 = X j ( F ( uj ( sj ) + \ jh ( s ; ) ) — H ( uj ) ) 1 ( F ( Uj ( sj ) + \ jh ( sj ) ) — F ( uj ( sj ) ) ) . From Lebourg's mean - value theorem there ...