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... V B3x $ 21 S2w B2t B2t Gs Charle G2e Gz S2w G2a + C3k 24 C3k Cn 19 Gz Cn S2W- Go Gr C3k Cn G2a G2e 25 C3k + G2a S2w S2W B2v S2w S2w 17 Cn B2u B2v B2u Ta Hg Cn 20 C31 Ta G2d Cn Gz Ta G2d C31 Gz Cn 30 G2d B2v $ 21 Wh 29 0 G2d Ta Wh B2x ...
... V - VERY SMALL METERS A 23.2- E 17.1-18.2 J 11.0-12.2 N 4.9-6.1 B 21.6-22.9 F 15.5-16.8 K 9.4-10.7 0 3.4-4.6 C 20.1 ... CN - COASTAL NATURAL CB - COASTAL BREAKWATER CT - COASTAL TIDE GATE RN - RIVER NATURAL RB - RIVER BASIN RT ...
... V - Fe 3 V d 0.285 4205.392m 4205.546m 4205.737 Cb ? - Fe 4198.734 ) 4205.902 CN CH ? 4198.863 -2N 4205.970 ) CN རཱ ༠ སཏྭཱ ༠ 1N 82 - 2N 4199.107m 4199.278 OPE Fe Y + -1 4199.379 ) -1 4199.526 4199.675 , CN -1 4199.745 ) CN -2 ...
... v cnu dn ( u + v ) , snu cnv dn ( u + v ) , sn v cnu = dnu sn ( u + v ) snu cn ( u + v ) = cnu dnv sn ( u + v ) snv cn ( u + v ) = cn v dnu sn ( u + v ) cnu sn ( u + v ) - — - · sn v dn ( u + v ) , snu dn ( u + v ) , = sn v dnu + snu ...
... cn'u , cn " u en u , cn'u , cn " " u dnu , dn'u , dn " u dnu , dn'u , dn " " u 65. Show that ( i ) s2 , ss ' , = k ... V 12 12 2 1 where = U ̧2Û‚2 V ̧2 V ̧1⁄2 [ U12sn'2u , sn2v1⁄2 – U2V1 sn'2u , sn ́2v1 ] U1 2 = 1 U2 × [ U12 sn2u1 ...
C.N. 47 227 C. N. 85 TABLE OF CASES REPORTED . TABLE OF CASES REPORTED . Cox , House v . Crampton v . Starr Crooke , National Trustees , & c . , Co. v . Currie and Others , The Queen v . PAGE 26 C.N. 21 Grant v . Spiller Gray ...
... viz . those involving three sides and an angle give cn ( u + v ) = c , c , s , s , dn ( u + v ) ... ................................. . ( 1 ) , c1 = c , cn ( u + v ) + s̟ , d , sn ( u + v ) ............ .. ( 2 ) , c2 = c , cn ( u + v ) + s , ...
... v . - And we thence deduce the subtraction formula , by writing , v for v , and therefore and dn v , viz . these are - snv for sn v but without altering cn v sn ( uv ) = sn u cn v dn v cn ( u - v ) = cn u cn v dn ( u — v ) = dn u dn v - -- ...
... v - 1 Cv - 1,1 + Ynv = 1 , = = 0 , v = n ; v # n ; from which we have y = · 0 , v = 0 , 1 , 2 , ( n − 1 ) ; Ynn = · 1 and ( 4 ) Yn , n + v = Cn , 1 Cn.2 1 0 0 0 0 Cn + 1,1 1 0 ( — ) v + 1 Cn , v - 2 Cn + 1 , v - 3 Cn + 2 , v - 4 1 0 v > 0 ...
... v ) cn ( u – v ) 1 + dn ( u + v ) dn ( u - v ) - as a function of sn2 u + sn2 v . ( Math . Trip . 1909. ) 6 . Shew that sn ( u - v ) dn ( u + v ) = sn u dn u cn vsn v dn v en u 1- k2 sn2 u sn2 v ( Jacobi . ) 7. Shew that { 1- ( 1 + k ...